html.longdesc.link.xml #1

<refentry xmlns="http://docbook.org/ns/docbook"
          xmlns:xlink="http://www.w3.org/1999/xlink"
          xmlns:xi="http://www.w3.org/2001/XInclude"
          xmlns:src="http://nwalsh.com/xmlns/litprog/fragment"
          xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
          version="5.0" xml:id="html.longdesc.link">
<refmeta>
<refentrytitle>html.longdesc.link</refentrytitle>
<refmiscinfo class="other" otherclass="datatype">boolean</refmiscinfo>
</refmeta>
<refnamediv>
<refname>html.longdesc.link</refname>
<refpurpose>Should a link to the longdesc be included in the HTML?</refpurpose>
</refnamediv>

<refsynopsisdiv>
<src:fragment xml:id="html.longdesc.link.frag">
<xsl:param name="html.longdesc.link" select="$html.longdesc"/>
</src:fragment>
</refsynopsisdiv>

<refsection><info><title>Description</title></info>

<para>If non-zero, links will be created to the
HTML files created for the
<literal>longdesc</literal> attribute. It makes no
sense to enable this option without also enabling the
<parameter>html.longdesc</parameter> parameter.</para>

<!--
<para>The <literal>longdesc.link</literal> named template is called
to construct the link.</para>
Assumption. That this documentation is for the user, do they need to know
how it's done?

-->

</refsection>
</refentry>